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Paulo Carrilho

Subject: Help! I need a XSL in order to swap nodes
Author: Paulo Carrilho
Date: 09 Mar 2006 08:05 AM

I've a project where the XML should be transformed.

If a tag exists in Output and Parameters, the Parameters one should be replaced by the Output corresponding and its childs.

Example: (XML In):

<RESULT>
<PARAMETERS>
<CYCLE>
<ENDDATE></ENDDATE>
<NUMBER>50</NUMBER>
</CYCLE>
<FILE>
<CHECK>Yes</CHECK>
</FILE>
<DIR>
<NAME>ONE</NAME>
</DIR>
<RUNTYPE>SAMPLE</RUNTYPE>
</PARAMETERS>
<OUTPUT jobfactor="71">
<CYCLE>
<NAME>MARY<\NAME>
<SURNAME>ROSE<\SURNAME>
</CYCLE>
<FILE>
<FILENAME>E:\ftphome\vodafone\xml\CC20060215S50.XML</FILENAME>
</FILE>
</OUTPUT>
</RESULT>

(XML Out):

<PARAMETERS>
<CYCLE>
<NAME>MARY<\NAME>
<SURNAME>ROSE<\SURNAME>
</CYCLE>
<FILE>
<FILENAME>E:\ftphome\vodafone\xml\CC20060215S50.XML</FILENAME>
</FILE>
<DIR>
<NAME>ONE</NAME>
</DIR>
<RUNTYPE>SAMPLE</RUNTYPE>
</PARAMETERS>

I've done somtehing like this:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="iso-8859-1"></xsl:output>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
<xsl:template match="OUTPUT"></xsl:template>
<xsl:template match="/RESULT/PARAMETERS/FILE">
<xsl:copy-of select="/RESULT/OUTPUT/FILE" />
</xsl:template>
</xsl:stylesheet>

but this only works if FILE exists, it is not generic. Might you help me, please?

Its urgent.

Minollo I.

Subject: Help! I need a XSL in order to swap nodes
Author: Minollo I.
Date: 09 Mar 2006 09:17 AM

You can try something like this:

<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="OUTPUT">
</xsl:template>
<xsl:template match="PARAMETERS">
<PARAMETERS>
<xsl:for-each select="*">
<xsl:variable name="elName" select="local-name()"/>
<xsl:choose>
<xsl:when test="../../OUTPUT/*[local-name()=$elName]">
<xsl:copy-of select="../../OUTPUT/*[local-name()=$elName]"/>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</PARAMETERS>
</xsl:template>

Paulo Carrilho

Subject: Help! I need a XSL in order to swap nodes
Author: Paulo Carrilho
Date: 09 Mar 2006 10:00 AM

Thank you!

However,

it doesnt' work.

It repeats the FILE (and its child) four times. and doesn't put the root (RESULT) neither the RUNTYPE tag

Minollo I.

Subject: Help! I need a XSL in order to swap nodes
Author: Minollo I.
Date: 09 Mar 2006 10:12 AM

Then you are either using a different XML source document from what you posted or you are not using the XSLT I posted, because what I get running that XSLT is:

<?xml version="1.0"?>
<PARAMETERS>
<CYCLE>
<NAME>MARY</NAME>
<SURNAME>ROSE</SURNAME>
</CYCLE>
<FILE>
<FILENAME>E:\ftphome\vodafone\xml\CC20060215S50.XML</FILENAME>
</FILE>
<DIR>
<NAME>ONE</NAME>
</DIR>
<RUNTYPE>SAMPLE</RUNTYPE>
</PARAMETERS>

I'm attaching the whole XSLT I'm using, for your reference.
Minollo

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